An airplane must be loaded so it is not too heavy and so its center of gravity (CG), the balance point, sits between the limits in its handbook. A CG too far forward or too far back makes the airplane hard, or impossible, to control. The math is the same as balancing a seesaw.
For learning only. This lesson is for studying and ground-school work, not for planning a real flight. Use official weather, charts and flight-planning tools, and the numbers in your aircraft’s handbook (POH).
Try it with your own problem ↓Empty airplane: 1,450 lb at 38.5 in. Pilot and front passenger: 340 lb at 37 in. Fuel: 30 gal at 48 in. Baggage: 40 lb at 95 in. The CG limits are 35 to 47.3 in, and the maximum weight is 2,300 lb. Is the airplane within limits?
Item Weight Arm Moment Empty 1,450 38.5 55,825 Front 340 37 12,580 Fuel 30 gal 180 48 8,640 Baggage 40 95 3,800 Total 2,010 80,845
The CG is 40.22 in behind the datum at 2,010 lb: inside both limits.
It is a seesaw. A weight’s tipping effect depends on how heavy it is and how far it is from the pivot, which is what weight × arm measures. The CG is the one point where the whole airplane’s weight could sit and tip it exactly as much as all the pieces together, so total moment ÷ total weight finds it. It is a weighted average of the arms.
Open The Flight Computer (free) with this example already filled in. It shows every step, and you can type over it with your own numbers.
Work it out: empty 1,450 lb, front seats 340 lb, 30 gal of fuel, 40 lb of baggageOpens The Flight Computer with this exampleOr try these
More aviation math, every step written out: open The Flight Computer.
How hard a weight tips the airplane about the datum: weight × distance, in pound-inches. A light bag far back can tip it as much as a heavy one near the datum.
Move weight (shift baggage forward or back) or take some off, and work it again. Never fly with the CG outside the limits.
Change in CG = weight moved × distance ÷ total weight = 40 × 58 ÷ 2,010 ≈ 1.15 in forward, from 40.22 to about 39.07 in.
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